|
Introductory Chemistry |
©
David W. Ball ; contributors: Maria Pugacheva, Maria del Mar Jimenez Quesada, Tatyana Sobolyeva, Oi Mi Lam et al. Source: Flat World Knowledge |
Chapter 4
Section B
Types of Chemical Reactions: Single- and Double-Displacement Reactions
Types of Chemical Reactions: Single- and Double-Displacement Reactions
Learning Objectives
|
-
Recognize chemical reactions as single-displacement reactions and double-displacement reactions.
-
Use the periodic table, activity series, and solubility rules to predict whether
single-displacement reactions or double-displacement reactions will occur.
|
Up to now, we have presented chemical reactions as a topic, but we have not discussed how the products of a chemical reaction
can be predicted. Here we will begin our study of certain types of chemical reactions that allow us to predict what the
products of the reaction will be.
The first two types of chemical reactions are single-displacement and double-displacement reactions (alternatively called
single-replacement or double-replacement). The main characteristic of these reactions is that one element is replaced by
another in a compound. As a result two new products are created.
A
single-replacement reaction is a chemical reaction where one element replaces another in a compound. For example,
2HCl(aq) + Zn(s) → ZnCl
2
(aq) + H
2
(g)
is an example of a single-replacement reaction. The hydrogen atoms in HCl are replaced by Zn atoms, and in the process a new
element—hydrogen—is formed. Another example of a single-replacement reaction is
2NaCl(aq) + F
2
(g) → 2NaF(s) + Cl
2
(g)
Here the negatively charged ion changes from chloride to fluoride. A typical characteristic of a single-replacement reaction is
that there is one element as a reactant and another element as a product.
Single-replacement reactions will occur because the replacing element is more reactive than the element in the compound. Let's
demonstrated this using fluorine, chlorine, bromine, and iodine as examples. Collectively, these elements are called the
halogens
and are in the next-to-last column on the periodic table (see Figure 4.1. “Halogens in the Periodic Table”). The reactivity of
elements in this group decreases from the top of the column to the bottom. Thus, an element located above another element will
replace it in a reaction, however, an element located below another element cannot replace the element located above it. For
example, chlorine will replace bromine, however, bromine cannot replace chlorine in a reaction. Thus, the following reaction
will occur:
CaI
2
(s) + Cl
2
(g) → CaCl
2
(s) + I
2
(s)
However, the reaction below will not occur because bromine is located below fluorine in the periodic table.
CaF
2
(s) + Br
2
(g) → CaBr
2
(s) + F
2
(g)
This is just one of many ways the periodic table is useful to understand chemistry.
Figure 4.1. Halogens in the Periodic Table
The halogens are the elements in the next-to-last column in the periodic table.
Example 2
Will a single-replacement reaction occur? If so, identify the products.
-
MgCl
2
+ I
2
→ ?
-
CaBr
2
+ F
2
→ ?
Solution
-
Since iodine is below chlorine on the periodic table and hence less reactive than chlorine, a single-replacement reaction will
not occur.
-
Since fluorine is above bromine on the periodic table, hence fluorine is more reactive than bromine, a single-replacement
reaction will occur, and the products of the reaction will be CaF
2
and Br
2
.
Test Yourself
Will a single-replacement reaction occur? If so, identify the products.
FeI
2
+ Cl
2
→ ?
Answer
Yes; FeCl
2
and I
2
|
Chemical reactivity trends are easy to predict when replacing anions in simple ionic compounds—simply use their relative
positions on the periodic table. However, when replacing the cations, the trends are not as straightforward. This is partly
because there are so many elements that can form cations; an element in one column on the periodic table may replace another
element nearby, or it may not. A list called the
activity series does the same thing the periodic table does for halogens: it lists the elements that will replace elements
below them in single-replacement reactions. A simple activity series is shown below.
Activity Series for Cation Replacement in Single-Replacement Reactions
-
Li
-
K
-
Ba
-
Sr
-
Ca
-
Na
-
Mg
-
Al
-
Mn
-
Zn
-
Cr
-
Fe
-
Ni
-
Sn
-
Pb
-
H
2
-
Cu
-
Ag
-
Hg
-
Pd
-
Pt
-
Au
Using the activity series is similar to using the positions of the halogens on the periodic table.
An element on top will replace an element below it in compounds undergoing a single-replacement
reaction. Elements will not replace elements above them in compounds.
Example 3
Use the activity series to predict the products, if any, of each equation.
-
FeCl
2
+ Zn → ?
-
HNO
3
+ Au → ?
Solution
-
Since zinc is above iron in the activity series, it will replace iron in the compound. The
products of this single-replacement reaction are ZnCl
2
and Fe.
-
Gold is below hydrogen in the activity series. As such, it will not replace hydrogen in a compound
with the nitrate ion. No reaction is predicted.
Test Yourself
Use the activity series to predict the products, if any, of this equation.
AlPO
4
+ Mg → ?
Answer
Mg
3
(PO
4
)
2
and Al
|
A
double-replacement reaction occurs when parts of two ionic compounds are exchanged, making two new compounds. A characteristic
of a double-replacement equation is that there are two compounds as reactants and two different compounds as products. An
example is
CuCl
2
(aq) + 2AgNO
3
(aq) → Cu(NO
3
)
2
(aq) + 2AgCl(s)
There are two equivalent ways of considering a double-replacement equation: either the cations are
swapped, or the anions are swapped. (You cannot swap both; you would end up with the same
substances you started with.) Either perspective should allow you to predict the proper products,
as long as you pair a cation with an anion and not a cation with a cation or an anion with an
anion.
Example 4
Predict the products of this double-replacement equation: BaCl
2
+ Na
2
SO
4
→ ?
Solution
Thinking about the reaction as either switching the cations or switching the anions, we would
expect the products to be BaSO
4
and NaCl.
Test Yourself
Predict the products of this double-replacement equation: KBr + AgNO
3
→ ?
Answer
KNO
3
and AgBr
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Predicting whether a double-replacement reaction occurs is somewhat more difficult than predicting
a single-replacement reaction. However, there is one type of double-replacement reaction that we
can predict: the precipitation reaction. A
precipitation reaction occurs when two ionic compounds are dissolved in water and form a new ionic compound that does not
dissolve; this new compound falls out of solution as a solid
precipitate. The formation of a solid precipitate is the driving force that makes the reaction proceed.
To judge whether double-replacement reactions will occur, we need to know what kinds of ionic
compounds form precipitates. For this, we use
solubility rules, which are general statements that predict which ionic compounds dissolve (are soluble) and which
do not (are not soluble or insoluble). Table 4.1. “Some Useful Solubility Rules” lists some general solubility rules. We need
to consider each ionic compound (both the reactants and the possible products) in light of the solubility rules in
Table 4.1. If a compound is soluble, we use the (aq) label with it, indicating it dissolves. If a compound
is not soluble, we use the (s) label with it and assume that it will precipitate out of solution. If everything is soluble,
then no reaction will be expected.
Table 4.1. Some Useful Solubility Rules
These compounds generally dissolve in water (are soluble):
|
Exceptions:
|
All compounds of Li
+
, Na
+
, K
+
, Rb
+
, Cs
+
, and NH
4
+
|
None
|
All compounds of NO
3
-
and C
2
H
3
O
2
-
|
None
|
Compounds of Cl
-
, Br
-
, I
-
|
Ag
+
, Hg
2
2+
, Pb
2+
|
Compounds of SO
4
2-
|
Hg
2
2+
, Pb
2+
, Sr
2+
, Ba
2+
|
These compounds generally do not dissolve in water (are insoluble):
|
Exceptions:
|
Compounds of CO
3
2-
and PO
4
3-
|
Compounds of Li
+
, Na
+
, K
+
, Rb
+
, Cs
+
, and NH
4
+
|
Compounds of OH
-
|
Compounds of Li
+
, Na
+
, K
+
, Rb
+
, Cs
+
, NH
4
+
, Sr
2+
, and Ba
2+
|
For example, consider the possible double-replacement reaction between Na
2
SO
4
and SrCl
2
. The solubility rules say that all ionic sodium compounds are soluble and all ionic chloride
compounds are soluble except for Ag
+
, Hg
2
2+
, and Pb
2+
, which are not being considered here. Therefore, Na
2
SO
4
and SrCl
2
are both soluble. The possible double-replacement reaction products are NaCl and SrSO
4
. Are these soluble? NaCl is (by the same rule we just quoted), but what about SrSO
4
? Compounds of the sulfate ion are generally soluble, but Sr
2+
is an exception: we expect it to be insoluble - a precipitate. Therefore, we expect a reaction to
occur, and the balanced chemical equation would be
Na
2
SO
4
(aq) + SrCl
2
(aq) → 2NaCl(aq) + SrSO
4
(s)
You would expect to see a visual change corresponding to SrSO
4
precipitating out of solution (Figure 4.2. “Double-Replacement Reactions”).
Figure 4.2. Double-Replacement Reactions
Some double-replacement reactions are obvious because you can see a solid precipitate coming out of
solution.
Example 5
Will a double-replacement reaction occur? If so, identify the products.
-
Ca(NO
3
)
2
+ KBr → ?
-
NaOH + FeCl
2
→ ?
Solution
-
According to the solubility rules, both Ca(NO
3
)
2
and KBr are soluble. Now we consider what the double-replacement products would be by switching the
cations (or the anions) - namely, CaBr
2
and KNO
3
. However, the solubility rules predict that these two substances would also be soluble, so no precipitate would form. Thus, we
predict no reaction in this case.
-
According to the solubility rules, both NaOH and FeCl
2
are expected to be soluble. If we assume that a double-replacement reaction may occur, we need to
consider the possible products, which would be NaCl and Fe(OH)
2
. NaCl is soluble, but, according to the solubility rules, Fe(OH)
2
is not soluble. Therefore, a reaction would occur, and Fe(OH)
2
(s) would precipitate out of solution. The balanced chemical equation is
2NaOH(aq) + FeCl
2
(aq) → 2NaCl(aq) + Fe(OH)
2
(s)
Test Yourself
Will a double-replacement equation occur? If so, identify the products.
Sr(NO
3
)
2
+ KCl → ?
Answer
No reaction; all possible products are soluble.
|
Key Takeaways
|
-
A single-replacement reaction replaces one element for another in a compound.
-
The periodic table or an activity series can help predict whether single-replacement reactions
occur.
-
A double-replacement reaction exchanges the cations (or the anions) of two ionic compounds.
-
A precipitation reaction is a double-replacement reaction in which one product is a solid
precipitate.
-
Solubility rules are used to predict whether some double-replacement reactions will occur.
|
Exercises
1.
|
What are the general characteristics that help you recognize single-replacement reactions?
|
One element replaces another element in a compound.
|
2.
|
What are the general characteristics that help you recognize double-replacement reactions?
|
Two parts of two compounds exchange to make two new compounds.
|
3.
|
Assuming that each single-replacement reaction occurs, predict the products and write each balanced
chemical equation.
-
Zn + Fe(NO
3
)
2
→ ?
-
F
2
+ FeI
3
→ ?
|
-
Zn + Fe(NO
3
)
2
→ Zn(NO
3
)
2
+ Fe
-
3F
2
+ 2FeI
3
→ 3I
2
+ 2FeF
3
|
4.
|
Assuming that each single-replacement reaction occurs, predict the products and write each balanced
chemical equation.
-
Li + MgSO
4
→ ?
-
NaBr + Cl
2
→ ?
|
-
2Li + MgSO
4
→ Li
2
SO
4
+ Mg
-
2NaBr + Cl
2
→ 2NaCl + Br
2
|
5.
|
Assuming that each single-replacement reaction occurs, predict the products and write each balanced
chemical equation.
-
Sn + H
2
SO
4
→ ?
-
Al + NiBr
2
→ ?
|
-
Sn + H
2
SO
4
→ SnSO
4
+ H
2
-
2Al + 3NiBr
2
→ 2AlBr
3
+ 3Ni
|
6.
|
Assuming that each single-replacement reaction occurs, predict the products and write each balanced
chemical equation.
-
Mg + HCl → ?
-
HI + Br
2
→ ?
|
-
Mg + 2HCl → MgCl
2
+ H
2
-
2HI + Br
2
→ 2HBr + I
2
|
7.
|
Use the periodic table or the activity series to predict if each single-replacement reaction will
occur and, if so, write a balanced chemical equation.
-
FeCl
2
+ Br
2
→ ?
-
Fe(NO
3
)
3
+ Al → ?
|
-
No reaction occurs.
-
Fe(NO
3
)
3
+ Al → Al(NO
3
)
3
+ Fe
|
8.
|
Use the periodic table or the activity series to predict if each single-replacement reaction will
occur and, if so, write a balanced chemical equation.
-
Zn + Fe
3
(PO
4
)
2
→ ?
-
Ag + HNO
3
→ ?
|
-
3Zn + Fe
3
(PO
4
)
2
→ Zn
3
(PO
4
)
2
+ 3Fe
-
No reaction occurs.
|
9.
|
Use the periodic table or the activity series to predict if each single-replacement reaction will
occur and, if so, write a balanced chemical equation.
-
NaI + Cl
2
→ ?
-
AgCl + Au → ?
|
-
2NaI + Cl
2
→ 2NaCl + I
2
-
No reaction occurs.
|
10.
|
Use the periodic table or the activity series to predict if each single-replacement reaction will
occur and, if so, write a balanced chemical equation.
-
Pt + H
3
PO
4
→ ?
-
Li + H
2
O → ? (Hint: treat H
2
O as if it were composed of H
+
and OH
ions.)
|
-
No reaction occurs.
-
2Li + 2H
2
O → 2LiOH + H
2
|
11.
|
Assuming that each double-replacement reaction occurs, predict the products and write each balanced
chemical equation.
-
Zn(NO
3
)
2
+ NaOH → ?
-
HCl + Na
2
S → ?
|
-
Zn(NO
3
)
2
+ 2NaOH → Zn(OH)
2
+ 2NaNO
3
-
2HCl + Na
2
S → 2NaCl + H
2
S
|
12.
|
Assuming that each double-replacement reaction occurs, predict the products and write each balanced
chemical equation.
-
Ca(C
2
H
3
O
2
)
2
+ HNO
3
→ ?
-
Na
2
CO
3
+ Sr(NO
2
)
2
→ ?
|
-
Ca(C
2
H
3
O
2
)
2
+ 2HNO
3
→ Ca(NO
3
)
2
+ 2C
2
H
4
O
2
-
Na
2
CO
3
+ Sr(NO
2
)
2
→ 2NaNO
2
+ SrCO
3
|
13.
|
Assuming that each double-replacement reaction occurs, predict the products and write each balanced
chemical equation.
-
Pb(NO
3
)
2
+ KBr → ?
-
K
2
O + MgCO
3
→ ?
|
-
Pb(NO
3
)
2
+ 2KBr → PbBr
2
+ 2KNO
3
-
K
2
O + MgCO
3
→ K
2
CO
3
+ MgO
|
14.
|
Assuming that each double-replacement reaction occurs, predict the products and write each balanced
chemical equation.
-
Sn(OH)
2
+ FeBr
3
→ ?
-
CsNO
3
+ KCl → ?
|
-
3Sn(OH)
2
+ 2FeBr
3
→ 3SnBr
2
+ 2Fe(OH)
3
-
CsNO
3
+ KCl → CsCl + KNO
3
|
15.
|
Use the solubility rules to predict if each double-replacement reaction will occur and, if so,
write a balanced chemical equation.
-
Pb(NO
3
)
2
+ KBr → ?
-
K
2
O + Na
2
CO
3
→ ?
|
-
Pb(NO
3
)
2
+ 2KBr → PbBr
2
(s) + 2KNO
3
-
No reaction occurs.
|
16.
|
Use the solubility rules to predict if each double-replacement reaction will occur and, if so,
write a balanced chemical equation.
-
Na
2
CO
3
+ Sr(NO
2
)
2
→ ?
-
(NH
4
)
2
SO
4
+ Ba(NO
3
)
2
→ ?
|
-
Na
2
CO
3
+ Sr(NO
2
)
2
→ SrCO
3
(s) + 2NaNO
2
-
(NH
4
)
2
SO
4
+ Ba(NO
3
)
2
→ 2NH
4
NO
3
+ BaSO
4
(s)
|
17.
|
Use the solubility rules to predict if each double-replacement reaction will occur and, if so,
write a balanced chemical equation.
-
K
3
PO
4
+ SrCl
2
→ ?
-
NaOH + MgCl
2
→ ?
|
-
2K
3
PO
4
+ 3SrCl
2
→ Sr
3
(PO
4
)
2
(s) + 6KCl
-
2NaOH + MgCl
2
→ 2NaCl + Mg(OH)
2
(s)
|
18.
|
Use the solubility rules to predict if each double-replacement reaction will occur and, if so,
write a balanced chemical equation.
-
KC
2
H
3
O
2
+ Li
2
CO
3
→ ?
-
KOH + AgNO
3
→ ?
|
-
No reaction occurs.
-
KOH + AgNO
3
→ AgOH(s) + KNO
3
|
|
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